sql - Select all records that match criteria plus next record that does not match criteria -

i've got table has columns this:

id, description, pc, account, amount 

i'm going looking 009 value in "pc" column, , each datum has sequentially-numbered unique id in "id" column. every datum 009 "pc" value have @ least 1 item following doesn't have "009" pc value.

is there way can write query that's real , similar fake code below? possible?

select   table.id id,   table.description description,   table.pc pc ((table.pc = 009) or (whatever, long table.id-1's "pc" value = 009)) 

if know ids sequential, can put logic in where clause:

select t.id, t.description, t.pc pc table t t.pc = 009 or       exists (select 1               table t2               t2.id = t.id - 1 , t2.pc = 009              ) order t.id;