algorithm - Java program gives incorrect Taylor series term for function e^x -

//java program asks user  input number e^x=1+x+x^2/2! +x^3/3!... e mathematical constant equal 2.718...  import java.util.scanner; public class taylor_2 {   public static void main(string args[]) {     scanner input=new scanner(system.in);     double x; //input x     double factorial=1; //initializes factorial     int counter=1; //initializes counter     double result=1; //initializes result      system.out.println("enter non negative number"); //asks user enter x     x=input.nextint();   //output in while loop continue generated if user doesn't entered negative number      while(x<1){       system.out.println("i said entered positive number");       x=input.nextint();     }     while(x>counter){       factorial=factorial*counter;//factorial formula       result=result+(math.pow(x,counter))/factorial; //equation e^x=1+x+x^2/2! +x^3/3!       counter++;     }     system.out.println("taylor series " +result);//output taylor equation e^x   } } 

here output of code:

enter non negative number

2

taylor series 4.0

when entered 2 , should have outputted 7.3890560983 instead of 4.0 since e=2.718... , e^2=7.3890560983. doing wrong?

the problem taylor series not same function e^x. return function close function e^x.

for understanding better, recommend second picture of next link:

https://en.wikipedia.org/wiki/taylor_series

you can see in previous picture n getting larger function getting more accurate.

your code's problem x value n value, , not true.

x: must value want e^x.

n: accurate of equation. larger means more accurate.

so must change while(x>counter) while(n>counter), n can either variable user selected accuracy, or constant selected accurcy.

i think until x=100, n=150 should work.

i hope helps you! :)