laravel - How to decouple eloquent from the service layer? -

i attempting create clean cut service layer, whereby service layer acts upon 1 or more repositories, , each repositories acts on own eloquent model.

for example, may have:

forumservice   |   +-- postrepo extends postinterface   |     |   |     +-- post (eloquent)   |   +-- userrepo extends userinterface         |         +-- user (eloquent) 

each service defines it's required dependencies via ioc. so, like:

// messageservice // .. public function __construct(userinterface $userrepository,                              messageinterface $messagerepository) {     // .. } 

my repositories resolved via bindings in respective service providers, such as:

class userrepositoryserviceprovider extends serviceprovider  {     public function register()     {         $this->app>bind(             'app\models\repositories\user\userinterface',             'app\models\repositories\user\userrepository');     } } 

this works fine. each service gets repositories requires.

to keep service layer clear of specific dependency on eloquent, leaves repo simple, immutable, data object.

key points in everyday language:

• only repo's talk own models directly
• repo's return simple, immutable, data objects
• services act tie multiple repo's , present simplified objects controllers, , views.

however can't come clean pattern associate eloquent models each other @ service or repo layer.

given post model has belongsto(user::class) relationship, how cleanly create relationship @ post repository layer.

i have tried:

public function associate($authorid)  {     $post->author()->associate($authorid); } 

but associate expects user eloquent object, not id. do:

public function associate($authorid)  {     $post->from()->associate($userrepo->findeloquent($authorid)); } 

but feel surfacing eloquent model repo shouldn't acting on it.

the easy way:

public function assigntoauthor($postid, $authorid)  {     $post = $this->find($postid); // or whatever method use find id      $post->author_id = $authorid; } 

now, above implies know foreign key author_id of relation. in order abstract bit, use this:

public function assigntoauthor($postid, $authorid)  {     $post = $this->find($postid);      $foreignkey = $post->author()->getforeignkey();      $post->{$foreignkey} = $authorid; } 

mind, still need save $post model, suppose know that.

---

depending on implementation of simple, immutable, data object use, allow passing objects instead of raw ids. between lines:

public function assigntoauthor($postid, $authorid)  {     if ($postid instanceof yourdataoject) {        $postid = $postid->getid();     }      if ($authorid instanceof yourdataoject) {        $authorid = $authorid->getid();     }      // ... }