python - replace values in list depending on value of current item and next item -

i trying use python code below output new list. output of print (words) should ['my','name','is','michael','apples','i','like','cars'].

right now, print (words) outputs ['cars']. missing here?

a = 'my name michael , cars' b = a.split() words = none i, j in enumerate(b):     words = []     if j == "and" , b[i+1][0] == "i":         words.append("apples")     else:         words.append(j) print (words) 

create words outside loop, see last word because keep setting words equal empty list each iteration:

words = [] # outside loop i, j in enumerate(b): 

if and happens last word indexerror. can set start index 1 in enumerate don't need +1 , avoid potential error indexing:

words = [] i, j in enumerate(b, 1):     if j == "and" , b[i][0] == "i": 

you can put in list comprehension:

a = 'my name michael , cars' b = a.split() words = ["apples" if wrd == "and" , b[i][0] == "i" else wrd i, wrd in enumerate(b,1)] print(words) ['my', 'name', 'is', 'michael', 'apples', 'like', 'cars'] 

you can avoid indexing using iter , next:

a = 'my name michael , cars' = iter(a.split()) words = ["apples" if wrd == "and" , next(it," ")[0] == "i" else wrd wrd in ] print(words) ['my', 'name', 'is', 'michael', 'apples', 'like', 'cars']