python - how do i properly make a for loop sit on one line, with commas and no spaces -

i'm new coding , it's little frustrating @ moment because have assessment outputs "1,2,fizz,4,buzz,fizz,7,8,fizz,buzz,11,fizz,13,14,fizzbuzz,16,17,fizz,19,buzz" , no cant use print.

code:

import sys num1=int(input('enter number range: ')) x in range(1,num1+1):    if x % 3 == 0:       print("fizz",end=" ")    if x % 5 == 0:       print('buzz',end=" ")    if x % 3 != 0 , x % 5 != 0:       print(str(x),end=" ") 

result: "enter number range?"(well 20)

1 2 fizz 4 buzz fizz 7 8 fizz buzz 11 fizz 13 14 fizz buzz 16 17 fizz 19 buzz  

so can see on same line don't want spaces, , want commas in between each number , letter accept number 15 should be, want 1 word "fizzbuzz", seen on example :

1,2,fizz,4,buzz,fizz,7,8,fizz,buzz,11,fizz,13,14,fizzbuzz,16,17,fizz,19,buzz 

this same question have answered here. if @ documentation print, says print variable number of objects (*objects in docs). print takes sep keyword, character(s) want separate printed objects with.

if modify code collect items-to-be-printed in list first , print @ once:

num1=int(input('enter number range: ')) items = list() x in range(1,num1+1):     if x % 3 == 0:         items.append("fizz")     if x % 5 == 0:         items.append('buzz')     if x % 3 != 0 , x % 5 != 0:         items.append(str(x))  print(*items, sep=',') 

when run it:

enter number range: 10 1,2,fizz,4,buzz,fizz,7,8,fizz,buzz 

for *objects-syntax can take @ so-question.

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to account numbers evenly divisible both 3 , 5:

num1=int(input('enter number range: ')) items = list() x in range(1,num1+1):     if x % 5 == 0 , x % 3 == 0:         items.append('fizzbuzz')     elif x % 3 == 0:         items.append("fizz")     elif x % 5 == 0:         items.append('buzz')     else:         items.append(str(x))  print(*items, sep=',')