php - How to write one login form for both the admin and the user -

i'm trying write code takes 2 input values( username , password) , compare them values in table (named user) in database. now, if value inserted username "admin" , password "admin". want direct admin page, , if user has inserted info, want direct him page also. codes below correct im giving no response. how can fixed

i wrote code html

<form name="userlogin" action="logincode.php" method="post" >             <h3>login</h3>              <table width="450px"> <tr>  <td valign="top">   <label for="first_name">your name *</label>  </td>  <td valign="top">      <input  type="text" name="user_username" maxlength="50" size="30" required>  </td> </tr>  <tr>  <td valign="top">   <label for="last_name">password *</label>  </td>  <td valign="top">      <input  type="password" name="user_password" maxlength="50" size="30" required>  </td>                 <tr>                     <td></td>                     <td><input type="submit" name="login" value="login" required>                     </td>                 </tr>             </table>          </form>  

and logincode.php

<?php  include ("../connections/map_connection.php"); if (isset($_post["login"])) {     $user_username = $_post["user_username"];     $user_password = $_post["user_password"];     /* $user_email=$_post["user_email"]; */      if ($username = 'admin' , $user_password = 'admin') {         $data = mysql_fetch_array($result);         session_start();         $_session['name'] = $data['user_username'];         $_session['start'] = time();         $_session['expire'] = $_session['start'] + 400;         header("location: ..admin/adminindex.php");     } else {         $sql = ("select * user user_username='$user_username' , user_password= '$user_password' ");         $result = mysql_query($sql);         if (!$result) {             echo "error" . mysql_error();         } else {             $row = mysql_num_rows($result);             if ($row == 0) {                 echo 'invalid username or password';             } else {                 $data = mysql_fetch_array($result);                 session_start();                 $_session['name'] = $data['user_username'];                 $_session['start'] = time();                 $_session['expire'] = $_session['start'] + 400;                 header("location: userindex.php");             }         }     } } ?> 

check if condition,

if ($username = 'admin' , $user_password = 'admin') 

here using single '=' i.e assignment operation instead of comparison i.e '=='.

try :

if ($username == 'admin' && $user_password == 'admin') 

:::::::::::::::::::::::update:::::::::::::::::::::::::

what mean?

if ($username == 'admin' && $user_password == 'admin') {  $data = mysql_fetch_array($result);  .... } 

my point without mysql_query() using mysql_fetch_assoc().