How to delete an array element in javascript without using any of built-in Array methods? -

i want write own implementation of array element deletion method. why? - because interested know algorithm behind array element deletion , take stab @ that.

i tried delete operator sets element undefined. don't want use of existing built-in methods of arrays such splice, shift, pop, etc.

is possible achieve this? not looking whole script idea , direction on how proceed help. may suggest me topics explore answer.

thanks.

p.s-1: have seen other posts related array element deletion use splice, pop, shift methods.

p.s-2: if going downvote question atleast have courtesy explain why downvoting. otherwise assume life extremely miserable , need downvote random questions posted on forum cure misery.

you can create own deletion method:

array.prototype.flush = function() {console.log(this.length = 0);} 

usage:

var test = [1, 2, 3]; alert(test); test.flush(); alert(test); 

update 1 deletion method: if understand correct: specify position, delete 1 element. if not better use array.prototype.splice(), anyhow, if asked:

code:

array.prototype.delete = function(pos){   if (pos < this.lenght) {   this.splice(pos, 1);     return  }   throw "index " + pos + " outside of array length"; } 

usage:

var test = [1, 2, 3];     alert(test);     test.delete (1);     alert(test); 

update 2 javascript array delete without prototype methods usage:

array.prototype.delete = function (pos) {   if (!this.length) throw 'array empty';   if (pos < this.length) {     (var = pos; < this.length - 1; i++) {       if (i < pos) continue;       this[i] = this[i + 1];     }     this.length = this.length - 1;     return this;   }   throw 'index ' + pos + ' outside of array length'; } var foo = [1, 2, 3]; foo.delete(0); alert(foo); foo.delete(0); alert(foo); foo.delete(0); alert(foo); foo.delete(0); alert(foo);